Wednesday, 16 October 2013

Capture and Navigate all the Links on Webpage

Iterator and advanced for loop can do similar job;  However, the inconsistency on page navigation within a loop can be solved using array concept.

private static String[] links = null;
private static int linksCount = 0;

driver.get("www.xyz.com");
List<WebElement> linksize = driver.findElements(By.tagName("a")); 
linksCount = linksize.size();
System.out.println("Total no of links Available: "+linksCount);
links= new String[linksCount];
System.out.println("List of links Available: "); 
// print all the links from webpage 
for(int i=0;i<linksCount;i++)
{
links[i] = linksize.get(i).getAttribute("href");
System.out.println(all_links_webpage.get(i).getAttribute("href"));
}
// navigate to each Link on the webpage
for(int i=0;i<linksCount;i++)
{
driver.navigate().to(links[i]);
Thread.sleep(3000);
}

1| Capture all links under specific frame|class|id and Navigate one by one
driver.get("www.xyz.com");  
WebElement element = driver.findElement(By.id(Value));
List<WebElement> elements = element.findElements(By.tagName("a"));
int sizeOfAllLinks = elements.size();
System.out.println(sizeOfAllLinks);
for(int i=0; i<sizeOfAllLinks ;i++)
{
System.out.println(elements.get(i).getAttribute("href"));
}   
for (int index=0; index<sizeOfAllLinks; index++ ) {
getElementWithIndex(By.tagName("a"), index).click();
driver.navigate().back();
}

public WebElement getElementWithIndex(By by, int index) {
WebElement element = driver.findElement(By.id(Value));
List<WebElement> elements = element.findElements(By.tagName("a")); 
return elements.get(index);
}

2| Capture all links [Alternate method]
#Java
driver.get(baseUrl + "https://www.google.co.in");
List<WebElement> all_links_webpage = driver.findElements(By.tagName("a")); 
System.out.println("Total no of links Available: " + all_links_webpage.size());
int k = all_links_webpage.size();
System.out.println("List of links Available: ");
for(int i=0;i<k;i++)
{
if(all_links_webpage.get(i).getAttribute("href").contains("google"))
{
String link = all_links_webpage.get(i).getAttribute("href");
System.out.println(link);
}   
}

#PYTHON
from selenium import webdriver

driver = webdriver.Firefox()
driver.get("https://www.google.co.in/")
Link = driver.find_elements_by_tag_name("a")
# prints size of all the links available
print len(Link) 

for index in Link:
    print index.get_attribute("href")

driver.quit()

5 comments:

  1. Good job...these code snippets are really useful for beginners to intermediate selenium testers...

    ReplyDelete
  2. Now how to make it regressive, that is from that link to other and from other....

    ReplyDelete
  3. Now how to make it regressive, that is from that link to other and from other....and navigate thru whole application from page to page.

    ReplyDelete
  4. Thanks for the great information in your blog Selenium Training in Chennai

    ReplyDelete